The kinetic energy of an object is given by the formula KE = 1/2 mv^2, where m is the mass and v is the velocity.

If the velocity is increased to six times its original velocity, we substitute 6v in place of v in the formula.

So, KE = 1/2 m(6v)^2 = 1/2 m(36v^2) = 18mv^2.

Therefore, the kinetic energy increases by a factor of 18 when the velocity is increased to six times its original velocity.

Question

The kinetic energy of an object is given by the formula KE = 1/2 mv^2, where m is the mass and v is the velocity.

If the velocity is increased to six times its original velocity, we substitute 6v in place of v in the formula.

So, KE = 1/2 m(6v)^2 = 1/2 m(36v^2) = 18mv^2.

Therefore, the kinetic energy increases by a factor of 18 when the velocity is increased to six times its original velocity.

Knowee AI · Accepted Answer

The kinetic energy of an object is given by the formula KE = 1/2 mv^2, where m is the mass and v is the velocity.

If the velocity is increased to six times its original velocity, we substitute 6v in place of v in the formula.

So, KE = 1/2 m(6v)^2 = 1/2 m(36v^2) = 18mv^2.

Therefore, the kinetic energy increases by a factor of 18 when the velocity is increased to six times its original velocity.

If a baseball's velocity is increased to six times its original velocity, by what factor does its kinetic energy increase?