Mark the proper output from the options belowimport numpy as npnames = np.array(["Reem" , "Salah" , "Haya" , "Maryam" , "Fatema"])names[2] = "Omar"print(names)A["Reem" "Salah" "Haya" "Maryam" "Fatema"]B["Reem" "Salah" "Omar" "Maryam" "Fatema"]C["Reem" "Haya" "Salah" "Maryam" "Fatema"]D["Reem" "Haya" "Maryam" "Fatema"]
Question
Mark the proper output from the options belowimport numpy as npnames = np.array(["Reem" , "Salah" , "Haya" , "Maryam" , "Fatema"])names[2] = "Omar"print(names)A["Reem" "Salah" "Haya" "Maryam" "Fatema"]B["Reem" "Salah" "Omar" "Maryam" "Fatema"]C["Reem" "Haya" "Salah" "Maryam" "Fatema"]D["Reem" "Haya" "Maryam" "Fatema"]
Solution 1
The correct answer is B["Reem" "Salah" "Omar" "Maryam" "Fatema"].
Here's the step by step explanation:
- We first import the numpy library using the command
import numpy as np. - We then create a numpy array
nameswith the elements "Reem", "Salah", "Haya", "Maryam", "Fatema". - The command
names[2] = "Omar"replaces the third element in the array (since Python uses 0-based indexing, the index 2 corresponds to the third element) with "Omar". So, "Haya" is replaced with "Omar". - Finally, when we print
names, the output will be ["Reem" "Salah" "Omar" "Maryam" "Fatema"].
Solution 2
The correct answer is B["Reem" "Salah" "Omar" "Maryam" "Fatema"]. This is because in the code, the element at index 2 of the numpy array 'names' is replaced with "Omar". The original element at index 2 was "Haya", so after the replacement, the array becomes ["Reem" "Salah" "Omar" "Maryam" "Fatema"].
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