Suppose one individual is randomly chosen. Find the probability that this person has an IQ less than 125.Write your answer in percent form. Round to the nearest tenth of a percent.P𝑃 (IQ less than 125) =

To answer this question, we need more information about the distribution of IQ scores in the population from which the individual is chosen. IQ scores are typically assumed to follow a normal distribution with a mean of 100 and a standard deviation of 15.

If we make this assumption, we can use a standard normal distribution table (or a calculator with normal distribution functions) to find the probability that a randomly chosen individual has an IQ less than 125.

Here are the steps:

1. Convert the IQ score to a z-score. The z-score is a measure of how many standard deviations an element is from the mean. The formula to calculate the z-score is:

   Z = (X - μ) / σ

   where X is the value we are interested in (in this case, 125), μ is the mean (100), and σ is the standard deviation (15).

   Z = (125 - 100) / 15 = 1.67

2. Look up the z-score in the standard normal distribution table. The value in the table tells us the probability that a value is less than our given value.

   The value for 1.67 is approximately 0.9525.

3. Convert this probability to a percentage and round to the nearest tenth of a percent.

   P = 0.9525 * 100 = 95.25%

So, if we assume that IQ scores are normally distributed with a mean of 100 and a standard deviation of 15, the probability that a randomly chosen individual has an IQ less than 125 is approximately 95.3%.