Bert and Birdie are in the same math class and are comparing their test scores from throughout the year. The following box plots were constructed from their test data.102030405060708090Bert's scoresBirdie's scoresTest scoresScoreWhich of the two students had a greater number of test scores of 8080 or higher?
Question
Bert and Birdie are in the same math class and are comparing their test scores from throughout the year. The following box plots were constructed from their test data.102030405060708090Bert's scoresBirdie's scoresTest scoresScoreWhich of the two students had a greater number of test scores of 8080 or higher?
Solution
The information provided does not include specific data or visual representation of the box plots for Bert's and Birdie's scores. Therefore, it's impossible to determine which of the two students had a greater number of test scores of 80 or higher. Please provide the necessary data or visual representation to answer the question.
Similar Questions
(3) The following boxplot shows the grades of two classes. Answer the following questions.Which class has a higher range?Which class has a smaller measure of spread?Compare the median grades of the two box plots.In class 2, what percentage of students have grades above 60?In class 1, what percentage of students have grades between 60 and 80?
Students in year 7 took an English test, The boy’s results are summarised below.The lowest mark was 12 The highest mark was 55 The median was 32The upper quartile was 41 The interquartile range was 22On the grid below, draw a box plot to represent this information.2. Students in year 7 took an English test.The girls’ results are summarised in the table below.15 17 17 21 26 2931 35 40 46 49 57Use the information in the table above to construct a box plot on the grid below.3. Year 8 students took a Maths test.The summary statistics for both boys and girls aresummarised below.3(a) Draw box plots for both sets of data on theaxes below.Boys GirisMedian 55 60Highest Value 82 78Range 48 38Upper Quartile 70 72Lower Quartile 42 453 (b) Compare the boxplots of the boys and girls.________4. Two classes, 8A and 8B, collect data on the time it takes students to get to school.This information has been summarised on the box plots below.4 (a) Fill in the table below.Class 8A 8BMedianInter - QuartileRangeRange4 (b) Which class was most consistent overall with the time they took to get to school?You must justify your answer.5. Two sets of data, A and B, have been plotted as box plots.(a) Which data set has the smallest inter - quartile range?(b) Why is only one characteristic “ whisker “ shown for data set B?(c) compare the distributions of box A and B.6. 5 friends measure their heights and the results are shown below.156 cm. 153 cm, 151 cm , 150 cm , 170 cmA box plot is to be made from this data.Discuss the benefits and drawbacks of using a box plot based on this data.Discuss the sample size and any outliers.7. Tom kept a record of the amount of time Robins spent in his garden at each visit.The table below shows his summary statistics for the times recorded.Robins MinutesLowest time 20Range 60Median 45Lower Quartile 30Interquartile range 28(a) on the grid below, draw a box plot to represent this information.(b) Tom logs some extra data about new Robins that have entered his garden,The new Robins spend the following times in the garden, 20 mins, 25 mins, 27 minsComment on how this will affect the shape of the box plot above.
Bob and Bert are debating about who did better on their exams. Bob got a 65 on the psychology exam and Bert got a 68 on the biology exam. Who did better? Explain.
Shown below are the marks scored by the students of two sections of a class. The strength of both sections is the same. Roll Number Section A Section BStudent 1 8.2 8.1Student 2 7.2 7.9Student 3 6.5 8.2Student 4 8.9 7.95Student 5 8.1 8.08Student 6 8 7.8Student 7 7.7 7.9Student 8 7.9 8.04Student 9 8.1 8.08Student 10 8.3 8.12Student 11 9 8.2Student 12 9 8Answer the following questions based on the table. Question 1/2MandatoryClass Performance: MeanCalculate the mean of marks scored by the students of each section.Section A: 8.075, Section B: 8.031Section A: 8.0, Section B: 8.3Section A: 7.3, Section B: 8.031Section A: 8.1, Section B: 8.031
Shown below are the marks scored by the students of two sections of a class. The strength of both sections is the same. Roll Number Section A Section BStudent 1 8.2 8.1Student 2 7.2 7.9Student 3 6.5 8.2Student 4 8.9 7.95Student 5 8.1 8.08Student 6 8 7.8Student 7 7.7 7.9Student 8 7.9 8.04Student 9 8.1 8.08Student 10 8.3 8.12Student 11 9 8.2Student 12 9 8Answer the following questions based on the table. Question 2/2MandatoryClass Performance: Standard DeviationAs you have learnt, standard deviation is a way of studying the variation in a dataset in the absence of outliers. So, calculate the standard deviation of each section of the class. You may use the STDEV.S function of MS Excel or STDEVA function of Google Sheets.Section A: 0.27, Section B: 0.45Section A: 0.73, Section B: 0.12Section A: 1.5, Section B: 1Section A: 1.04, Section B: 0.02
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