When butane reacts with bromine in the presence of light, a substitution reaction, specifically a radical halogenation, occurs. This reaction can result in multiple products due to the different positions the bromine can attach to the butane molecule. Here are two possible products:

1. 1-bromobutane: This is formed when a hydrogen atom from one of the end carbon atoms in butane is replaced by a bromine atom.

2. 2-bromobutane: This is formed when a hydrogen atom from one of the middle carbon atoms in butane is replaced by a bromine atom.

The reaction can be summarized as follows:

C4H10 + Br2 → C4H9Br + HBr

The exact product and its quantity depend on the specific conditions of the reaction, including temperature, concentration, and the presence of any catalysts.

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When butane reacts with bromine in the presence of light, a substitution reaction, specifically a radical halogenation, occurs. This reaction can result in multiple products due to the different positions the bromine can attach to the butane molecule. Here are two possible products:

1. 1-bromobutane: This is formed when a hydrogen atom from one of the end carbon atoms in butane is replaced by a bromine atom.

2. 2-bromobutane: This is formed when a hydrogen atom from one of the middle carbon atoms in butane is replaced by a bromine atom.

The reaction can be summarized as follows:

C4H10 + Br2 → C4H9Br + HBr

The exact product and its quantity depend on the specific conditions of the reaction, including temperature, concentration, and the presence of any catalysts.

Knowee AI · Accepted Answer

When butane reacts with bromine in the presence of light, a substitution reaction, specifically a radical halogenation, occurs. This reaction can result in multiple products due to the different positions the bromine can attach to the butane molecule. Here are two possible products:

1. 1-bromobutane: This is formed when a hydrogen atom from one of the end carbon atoms in butane is replaced by a bromine atom.

2. 2-bromobutane: This is formed when a hydrogen atom from one of the middle carbon atoms in butane is replaced by a bromine atom.

The reaction can be summarized as follows:

C4H10 + Br2 → C4H9Br + HBr

The exact product and its quantity depend on the specific conditions of the reaction, including temperature, concentration, and the presence of any catalysts.

Alkanes react with chlorine in the presence of light. They also react with bromine in a similar way. What are two possible products that will be formed when butane reacts with bromine in the presence of light?

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