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Recall that a factor of a number divides the original number and leaves no remainder. For example, 4 and 6 are factors of 12.  Find all factors of 24.

Question

Recall that a factor of a number divides the original number and leaves no remainder. For example, 4 and 6 are factors of 12.  Find all factors of 24.

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Solution

Sure, here are the factors of 24:

Step 1: Start by dividing the number 24 with the smallest prime number, i.e., 2. 24 divided by 2 is 12, which is an integer. So, 2 is a factor of 24.

Step 2: Continue with the number 2. 12 divided by 2 is 6, which is an integer. So, 2 is a factor again.

Step 3: Continue with the number 2. 6 divided by 2 is 3, which is an integer. So, 2 is a factor again.

Step 4: Now, try to divide 3, the last obtained number, by 2. It does not result in an integer. So, 2 is not a factor anymore.

Step 5: Proceed with the next prime number, i.e., 3. 3 divided by 3 is 1, which is an integer. So, 3 is a factor.

Step 6: Now, if we continue with 1, we won't get any new factors. So, we stop here.

So, the factors of 24 are 2, 2, 2, and 3. But we usually list each factor only once, and we also include the number 1 (which is a factor of every number) and the number itself. So, the complete list of factors of 24 is 1, 2, 3, 4, 6, 8, 12, and 24.

This problem has been solved

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