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A boat having a length 5 m and width 4 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of man is _________ Kg.

Question

A boat having a length 5 m and width 4 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of man is _________ Kg.

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Solution

To find the mass of the man, we need to use the principle of buoyancy, which states that the weight of the water displaced by an object is equal to the weight of the object.

Step 1: Calculate the volume of water displaced The boat sinks by 1 cm when the man gets on it. This means that the volume of the water displaced is equal to the volume of the boat that is submerged when the man is on it.

The volume (V) of a rectangular prism (like the submerged part of the boat) is calculated by multiplying the length (L), width (W), and height (H). In this case, the length and width of the boat are 5 m and 4 m respectively, and the height is the amount the boat sinks, which is 1 cm or 0.01 m.

So, V = L * W * H = 5 m * 4 m * 0.01 m = 0.2 cubic meters.

Step 2: Calculate the weight of the water displaced The weight (W) of an object is calculated by multiplying its volume (V) by the density (D) of the material it's made of, and by the acceleration due to gravity (g).

The density of water is approximately 1000 kg/m^3, and the acceleration due to gravity is approximately 9.8 m/s^2.

So, W = V * D * g = 0.2 m^3 * 1000 kg/m^3 * 9.8 m/s^2 = 1960 N.

Step 3: Convert the weight to mass The weight of an object is related to its mass (m) by the equation W = m * g. Therefore, we can find the mass of the man by rearranging this equation to m = W / g.

So, m = 1960 N / 9.8 m/s^2 = 200 kg.

Therefore, the mass of the man is 200 kg.

This problem has been solved

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