In a chemistry experiment, the volume of a liquid is measured three times as 55 mL, 57 mL, and 56 mL. If the actual volume is 56.5 mL, what is the percent error of the average measurement?Select one:a.0.0088b.0.0106c.0.0053d.0.0044
Question
In a chemistry experiment, the volume of a liquid is measured three times as 55 mL, 57 mL, and 56 mL. If the actual volume is 56.5 mL, what is the percent error of the average measurement?Select one:a.0.0088b.0.0106c.0.0053d.0.0044
Solution
To solve this problem, follow these steps:
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First, find the average of the measured volumes. Add the three measurements together and divide by the number of measurements:
(55 mL + 57 mL + 56 mL) / 3 = 56 mL
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Next, calculate the difference between the actual volume and the average measured volume:
|56.5 mL - 56 mL| = 0.5 mL
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Then, calculate the percent error by dividing the absolute difference by the actual volume and multiplying by 100%:
(0.5 mL / 56.5 mL) * 100% = 0.0088 or 0.88%
So, the percent error of the average measurement is 0.88%, which corresponds to option a. 0.0088.
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