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The code snippet below takes a character as input and prints as "alphabet", "digit" or "special character" depending on character provided as input.Choose the apt option to do this.       Scanner sc=new Scanner(System.in);       char ch = sc.next().charAt(0);        if( )              System.out.println(ch+" is an alphabet");        else if( )              System.out.println(ch+" is a digit");        else              System.out.println(ch+" is a special character");

Question

The code snippet below takes a character as input and prints as "alphabet", "digit" or "special character" depending on character provided as input.Choose the apt option to do this.       Scanner sc=new Scanner(System.in);       char ch = sc.next().charAt(0);        if( )              System.out.println(ch+" is an alphabet");        else if( )              System.out.println(ch+" is a digit");        else              System.out.println(ch+" is a special character");

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Solution

Here is the Java code snippet that will do this:

Scanner sc=new Scanner(System.in);
char ch = sc.next().charAt(0);
if((ch >= 'a' && ch <= 'z') || (ch >= 'A' && ch <= 'Z'))
    System.out.println(ch+" is an alphabet");
else if(ch >= '0' && ch <= '9')
    System.out.println(ch+" is a digit");
else
    System.out.println(ch+" is a special character");

This code works by checking if the character is within the ASCII range for lowercase or uppercase letters (for alphabets), or within the range for digits. If it's not in either of these ranges, it's considered a special character.

This problem has been solved

Similar Questions

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