Fill in the blank to complete the function create_I_matrix( ) { int* matrix = malloc(sizeof(int) * length); for(int row = 0; row < length; row++) { for(int column = 0; column < length; column++) { if(row == column) { matrix[ row ][ column ] = 1; } else { matrix[ row ][ column ] = 0; } } } return matrix;}
Question
Fill in the blank to complete the function create_I_matrix( ) { int* matrix = malloc(sizeof(int) * length); for(int row = 0; row < length; row++) { for(int column = 0; column < length; column++) { if(row == column) { matrix[ row ][ column ] = 1; } else { matrix[ row ][ column ] = 0; } } } return matrix;}
Solution
The function you provided is written in C, but it seems to have a mistake. In C, you can't directly create a 2D array using a single pointer. You need to use a pointer to a pointer. Here is the corrected function:
int** create_I_matrix(int length) {
int** matrix = (int**)malloc(length * sizeof(int*));
for(int i = 0; i < length; i++)
matrix[i] = (int*)malloc(length * sizeof(int));
for(int row = 0; row < length; row++) {
for(int column = 0; column < length; column++) {
if(row == column) {
matrix[row][column] = 1;
} else {
matrix[row][column] = 0;
}
}
}
return matrix;
}
This function creates a 2D identity matrix of size length x length. It first allocates memory for length number of pointers, then for each pointer, it allocates memory for length number of integers. It then fills the matrix such that the diagonal elements are 1 and the rest are 0.
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