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Suppose we want to choose 6 colors, without replacement, from 11 distinct colors.(If necessary, consult a list of formulas.)(a) If the order of the choices is taken into consideration, how many ways can this be done?(b) If the order of the choices is not taken into consideration, how many ways can this be done?

Question

Suppose we want to choose 6 colors, without replacement, from 11 distinct colors.(If necessary, consult a list of formulas.)(a) If the order of the choices is taken into consideration, how many ways can this be done?(b) If the order of the choices is not taken into consideration, how many ways can this be done?

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Solution

(a) If the order of the choices is taken into consideration, this is a permutation problem. The formula for permutations is P(n, r) = n! / (n-r)!. Here, n is the total number of items to choose from (11 colors), and r is the number of items to choose (6 colors). So, P(11, 6) = 11! / (11-6)! = 1110987*6 = 332,640 ways.

(b) If the order of the choices is not taken into consideration, this is a combination problem. The formula for combinations is C(n, r) = n! / [r!(n-r)!]. Here, n is the total number of items to choose from (11 colors), and r is the number of items to choose (6 colors). So, C(11, 6) = 11! / [6!(11-6)!] = 1110987 / (65432*1) = 462 ways.

This problem has been solved

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