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int i = 5;int j = 4 + i;System.out.println( i );System.out.print( "i");System.out.println( i + j);System.out.println("i + j = " + i + j);System.out.println("This is the number + i.");

Question

int i = 5;int j = 4 + i;System.out.println( i );System.out.print( "i");System.out.println( i + j);System.out.println("i + j = " + i + j);System.out.println("This is the number + i.");

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Solution

The code you've written is in Java. Here's a step-by-step explanation of what it does:

  1. int i = 5; This line declares an integer variable i and assigns it the value 5.

  2. int j = 4 + i; This line declares an integer variable j and assigns it the value of 4 + i. Since i is 5, j becomes 9.

  3. System.out.println( i ); This line prints the value of i, which is 5, to the console. It also adds a new line after printing.

  4. System.out.print( "i"); This line prints the string "i" to the console. It does not add a new line after printing, so the next print statement will continue on the same line.

  5. System.out.println( i + j); This line prints the sum of i and j, which is 14, to the console. It also adds a new line after printing.

  6. System.out.println("i + j = " + i + j); This line prints the string "i + j = ", followed by the value of i, followed by the value of j. However, because the + operator is used for both addition and string concatenation in Java, and because the operands are evaluated from left to right, this will actually print "i + j = 59", not "i + j = 14". To get the latter, you would need to use parentheses to change the order of operations: "i + j = " + (i + j).

  7. System.out.println("This is the number + i."); This line prints the string "This is the number + i." to the console. It does not substitute the value of i into the string; to do that, you would need to use the + operator: "This is the number " + i + ".".

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