int i = 5;int j = 4 + i;System.out.println( i );System.out.print( "i");System.out.println( i + j);System.out.println("i + j = " + i + j);System.out.println("This is the number + i.");
Question
int i = 5;int j = 4 + i;System.out.println( i );System.out.print( "i");System.out.println( i + j);System.out.println("i + j = " + i + j);System.out.println("This is the number + i.");
Solution
The code you've written is in Java. Here's a step-by-step explanation of what it does:
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int i = 5;This line declares an integer variableiand assigns it the value5. -
int j = 4 + i;This line declares an integer variablejand assigns it the value of4 + i. Sinceiis5,jbecomes9. -
System.out.println( i );This line prints the value ofi, which is5, to the console. It also adds a new line after printing. -
System.out.print( "i");This line prints the string "i" to the console. It does not add a new line after printing, so the next print statement will continue on the same line. -
System.out.println( i + j);This line prints the sum ofiandj, which is14, to the console. It also adds a new line after printing. -
System.out.println("i + j = " + i + j);This line prints the string "i + j = ", followed by the value ofi, followed by the value ofj. However, because the+operator is used for both addition and string concatenation in Java, and because the operands are evaluated from left to right, this will actually print "i + j = 59", not "i + j = 14". To get the latter, you would need to use parentheses to change the order of operations:"i + j = " + (i + j). -
System.out.println("This is the number + i.");This line prints the string "This is the number + i." to the console. It does not substitute the value ofiinto the string; to do that, you would need to use the+operator:"This is the number " + i + ".".
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