Let's solve this step by step:

Step 1: Let's denote the distance between the house and the school as 'd' km.

Step 2: The boy goes to school at a speed of 4 km/h, so the time taken to go to school is d/4 hours.

Step 3: He returns home at a speed of 3 km/h, so the time taken to return home is d/3 hours.

Step 4: According to the problem, the total time taken for going and coming is 7 hours. So, we can set up the equation: d/4 + d/3 = 7.

Step 5: To solve for 'd', we first need to find a common denominator for the fractions, which is 12 in this case. So, the equation becomes: 3d/12 + 4d/12 = 7.

Step 6: Simplifying the equation gives: 7d/12 = 7.

Step 7: Solving for 'd' gives: d = 7 * 12 / 7 = 12 km.

So, the distance between the house and the school is 12 km. Therefore, the correct answer is not in the options given. There might be a mistake in the problem or the options provided.

Question

Let's solve this step by step:

Step 1: Let's denote the distance between the house and the school as 'd' km.

Step 2: The boy goes to school at a speed of 4 km/h, so the time taken to go to school is d/4 hours.

Step 3: He returns home at a speed of 3 km/h, so the time taken to return home is d/3 hours.

Step 4: According to the problem, the total time taken for going and coming is 7 hours. So, we can set up the equation: d/4 + d/3 = 7.

Step 5: To solve for 'd', we first need to find a common denominator for the fractions, which is 12 in this case. So, the equation becomes: 3d/12 + 4d/12 = 7.

Step 6: Simplifying the equation gives: 7d/12 = 7.

Step 7: Solving for 'd' gives: d = 7 * 12 / 7 = 12 km.

So, the distance between the house and the school is 12 km. Therefore, the correct answer is not in the options given. There might be a mistake in the problem or the options provided.

Knowee AI · Accepted Answer

Let's solve this step by step:

Step 1: Let's denote the distance between the house and the school as 'd' km.

Step 2: The boy goes to school at a speed of 4 km/h, so the time taken to go to school is d/4 hours.

Step 3: He returns home at a speed of 3 km/h, so the time taken to return home is d/3 hours.

Step 4: According to the problem, the total time taken for going and coming is 7 hours. So, we can set up the equation: d/4 + d/3 = 7.

Step 5: To solve for 'd', we first need to find a common denominator for the fractions, which is 12 in this case. So, the equation becomes: 3d/12 + 4d/12 = 7.

Step 6: Simplifying the equation gives: 7d/12 = 7.

Step 7: Solving for 'd' gives: d = 7 * 12 / 7 = 12 km.

So, the distance between the house and the school is 12 km. Therefore, the correct answer is not in the options given. There might be a mistake in the problem or the options provided.

A boy goes to his school from his house at a speed of 4 km/h and return back to the home at the speed of 3 km/h. if he takes total time 7 hours in going and coming then what is the distance between home and college?A)30kmB)20kmC)21kmD)24km

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