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Consider the following function:f left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left columnspacing 1.4ex end attributes row cell left parenthesis x plus 1 right parenthesis squared end cell cell i f space x less or equal than 3 end cell row cell short dash 2 x plus 22 end cell cell i f space x greater than 3 end cell end table closeDetermine if f left parenthesis x right parenthesis is continuous at x equals 3. If not, select the option with the correct reasoning as to why not.A. Continuous at x equals 3B. Not continuous at x equals 3 because limit as x rightwards arrow 3 of f left parenthesis x right parenthesis not equal to f left parenthesis 3 right parenthesisC. Not continuous at x equals 3 because limit as x rightwards arrow 3 of f left parenthesis x right parenthesis does not existD. Not continuous at x equals 3 because f left parenthesis 3 right parenthesis is undefined

Question

Consider the following function:f left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left columnspacing 1.4ex end attributes row cell left parenthesis x plus 1 right parenthesis squared end cell cell i f space x less or equal than 3 end cell row cell short dash 2 x plus 22 end cell cell i f space x greater than 3 end cell end table closeDetermine if f left parenthesis x right parenthesis is continuous at x equals 3. If not, select the option with the correct reasoning as to why not.A. Continuous at x equals 3B. Not continuous at x equals 3 because limit as x rightwards arrow 3 of f left parenthesis x right parenthesis not equal to f left parenthesis 3 right parenthesisC. Not continuous at x equals 3 because limit as x rightwards arrow 3 of f left parenthesis x right parenthesis does not existD. Not continuous at x equals 3 because f left parenthesis 3 right parenthesis is undefined

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Solution

To determine if the function f(x) is continuous at x=3, we need to check three conditions:

  1. f(3) is defined.
  2. The limit as x approaches 3 of f(x) exists.
  3. The limit as x approaches 3 of f(x) equals f(3).

Let's check these conditions step by step:

  1. f(3) is defined: For x<=3, f(x) = (x+1)^2. So, f(3) = (3+1)^2 = 16.

  2. The limit as x approaches 3 of f(x) exists: We need to check the limit from the left and the right side of 3.

    From the left side (x<=3), f(x) = (x+1)^2. So, the limit as x approaches 3 from the left is (3+1)^2 = 16.

    From the right side (x>3), f(x) = -2x + 22. So, the limit as x approaches 3 from the right is -2*3 + 22 = 16.

    Since the limit from the left and the right are equal, the limit as x approaches 3 of f(x) exists and is 16.

  3. The limit as x approaches 3 of f(x) equals f(3): As we found in the previous steps, both the limit as x approaches 3 of f(x) and f(3) are 16.

Since all three conditions are met, the function f(x) is continuous at x=3. So, the correct answer is A. Continuous at x equals 3.

This problem has been solved

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