Given a potential of V= 24 V across a capacitor which has a capacitance of C = 2 micro Farads, what is the energy stored by the capacitor in Joules?
Question
Given a potential of V= 24 V across a capacitor which has a capacitance of C = 2 micro Farads, what is the energy stored by the capacitor in Joules?
Solution
The energy (E) stored in a capacitor can be calculated using the formula:
E = 1/2 * C * V^2
Where: E is the energy in joules (J) C is the capacitance in farads (F) V is the potential difference in volts (V)
Here are the steps to calculate the energy:
-
Identify the capacitance (C). In this case, the capacitance is 2 microfarads, which is 2 * 10^-6 farads.
-
Identify the potential difference (V). In this case, the potential difference is 24 volts.
-
Substitute the values into the formula and calculate the energy (E) in joules.
E = 1/2 * C * V^2 E = 1/2 * 2 * 10^-6 F * (24 V)^2 E = 0.000001 F * 576 V^2 E = 0.576 J
Therefore, the energy stored by the capacitor is 0.576 joules.
Similar Questions
A capacitor of capacitance C and potential V has energy E. It is connected to another capacitor of capacitance 2C and potential 2 V. Then the loss of energy is x3E, where x is_____
A capacitor of capacitance 10 µF is charged to a potential of 50 V. The energy stored in the capacitor is:a) 12.5 Jb) 1.25 Jc) 0.125 Jd) 25 J
How much energy is stored in a fully charged capacitor with 1.2 × 10^−9 C of charge on one plate and 16 V across its plates?
or the circuit shown below, calculate the initial energy stored in the capacitor.
Two capacitors, one 12.0 𝜇𝐹 and the other of unknown capacitance C, are connected in parallel across a battery with an emf of 9.00 V. The total energy stored in the two capacitors is 0.0115 J. Determine the capacitance C.a.272 𝜇𝐹b.180 𝜇𝐹c.12 𝜇𝐹d.284𝜇𝐹
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.