The number of zeroes at the end of a product is determined by the number of pairs of 2 and 5 in its prime factorization, because 2*5 = 10.

In the given series 1, 3, 5, 7, ..., 99, all numbers are odd. Therefore, they do not have 2 in their prime factorization.

Without a 2, we cannot form a pair of 2 and 5, regardless of the number of 5s.

Therefore, the product of the numbers in this series will not end in a zero.

So, the answer is Nil.

Question

The number of zeroes at the end of a product is determined by the number of pairs of 2 and 5 in its prime factorization, because 2*5 = 10.

In the given series 1, 3, 5, 7, ..., 99, all numbers are odd. Therefore, they do not have 2 in their prime factorization.

Without a 2, we cannot form a pair of 2 and 5, regardless of the number of 5s.

Therefore, the product of the numbers in this series will not end in a zero.

So, the answer is Nil.

Knowee AI · Accepted Answer

The number of zeroes at the end of a product is determined by the number of pairs of 2 and 5 in its prime factorization, because 2*5 = 10.

In the given series 1, 3, 5, 7, ..., 99, all numbers are odd. Therefore, they do not have 2 in their prime factorization.

Without a 2, we cannot form a pair of 2 and 5, regardless of the number of 5s.

Therefore, the product of the numbers in this series will not end in a zero.

So, the answer is Nil.

What will be the number of zeroes at the end of the product of 1, 3, 5, 7 ….. 99?*1 point10111Nill