4. A reaction mixture initially containing vitamin C at 0.0112 M, H2O2 at 0.14 M, and iodide ion at 0.03 M. The mixture turns from colorless to dark blue-black after 24.7 seconds. Calculate the rate of this reaction if the final iodide concentration is 0.013 M.
Question
- A reaction mixture initially containing vitamin C at 0.0112 M, H2O2 at 0.14 M, and iodide ion at 0.03 M. The mixture turns from colorless to dark blue-black after 24.7 seconds. Calculate the rate of this reaction if the final iodide concentration is 0.013 M.
Solution
The rate of a reaction is calculated by the change in concentration of reactants or products over the change in time. In this case, we are given the initial and final concentrations of iodide ion and the time it takes for the reaction to occur.
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First, we need to find the change in concentration of iodide ion. This is done by subtracting the final concentration from the initial concentration.
Change in concentration = Initial concentration - Final concentration = 0.03 M - 0.013 M = 0.017 M
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Next, we need to convert the time from seconds to minutes because the rate of reaction is usually expressed in M/min.
Time = 24.7 seconds ÷ 60 = 0.4117 minutes
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Finally, we calculate the rate of the reaction by dividing the change in concentration by the change in time.
Rate of reaction = Change in concentration ÷ Time = 0.017 M ÷ 0.4117 min = 0.0413 M/min
So, the rate of this reaction is 0.0413 M/min.
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