The balanced equation for the conversion of sodium nitrate to sodium nitrite and oxygen is: 2NaNO3 → 2NaNO2 + O2. How many moles of oxygen will be produced from 3.6 moles of sodium nitrate?
Question
The balanced equation for the conversion of sodium nitrate to sodium nitrite and oxygen is: 2NaNO3 → 2NaNO2 + O2. How many moles of oxygen will be produced from 3.6 moles of sodium nitrate?
Solution
From the balanced chemical equation, we can see that 2 moles of sodium nitrate (NaNO3) produce 1 mole of oxygen (O2).
Therefore, the ratio of NaNO3 to O2 is 2:1.
Given that we have 3.6 moles of sodium nitrate, we can use this ratio to find out how many moles of oxygen will be produced.
(3.6 moles NaNO3) * (1 mole O2 / 2 moles NaNO3) = 1.8 moles O2
So, 1.8 moles of oxygen will be produced from 3.6 moles of sodium nitrate.
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