What is the output of this code? int y = 0;                  while(y < 14)                  {                    y++;                    for(int i = 1; i < 4; i++)                    {                      y += i;                    }                  }                  System.out.println(y);Select one:This program writes "14" to the standard output.This program writes "13" to the standard output.This program writes "21" to the standard output.This program writes "15" to the standard output.

The output of this code will be "21". Here's the step by step explanation:

1. The variable y is initialized to 0.
2. The while loop will continue to run as long as y is less than 14.
3. In each iteration of the while loop, y is incremented by 1 (y++).
4. Then a for loop runs from 1 to 3 (inclusive), and in each iteration of this for loop, y is increased by i (y += i).
5. So in each iteration of the while loop, y is increased by 1 (from the y++) and then by 1, 2, and 3 (from the for loop). This means y is increased by a total of 7 in each iteration of the while loop.
6. The while loop will stop running once y is no longer less than 14. This happens after the second iteration of the while loop, at which point y is 14.
7. However, the condition of the while loop (y < 14) is only checked at the start of each iteration, not in the middle of an iteration. So once the second iteration starts, it will run to completion, even though y becomes 14 in the middle of this iteration.
8. Therefore, y is increased by another 7 during the second iteration of the while loop, bringing it to 21.
9. At this point, the while loop ends, and y is printed out, so "21" is the output.