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If area of rectangle is 4x^2 + 4x - 3 then it’s possible dimensions are

Question

If area of rectangle is 4x^2 + 4x - 3 then it’s possible dimensions are

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Solution

The area of a rectangle is given by the product of its length and width. In this case, the area is given as a quadratic expression, 4x^2 + 4x - 3.

To find the possible dimensions of the rectangle, we need to factorize this quadratic expression.

The quadratic expression can be written in the form ax^2 + bx + c. Here, a = 4, b = 4, and c = -3.

We can factorize the quadratic expression by finding two numbers that multiply to give ac (which is -12 in this case) and add up to give b (which is 4 in this case).

The numbers that satisfy these conditions are 6 and -2 because 6*-2 = -12 and 6 + (-2) = 4.

So, we can write the quadratic expression as 4x^2 + 6x - 2x - 3.

Now, we can factor by grouping:

4x^2 + 6x - 2x - 3 = 2x(2x + 3) -1(2x + 3)

So, the factored form of the quadratic expression is (2x + 3)(2x - 1).

Therefore, the possible dimensions of the rectangle are (2x + 3) and (2x - 1).

This problem has been solved

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