At a given temperature, total vapour pressure in Torr of a mixture of volatile components A andB is given byPTotal = 120 – 75 XBhence, vapour pressure of pure A and B respectively (in Torr) are
Question
At a given temperature, total vapour pressure in Torr of a mixture of volatile components A andB is given byPTotal = 120 – 75 XBhence, vapour pressure of pure A and B respectively (in Torr) are
Solution
To find the vapor pressure of pure components A and B, we can use the given equation:
PTotal = 120 - 75 XB
Here, PTotal represents the total vapor pressure of the mixture, XB represents the mole fraction of component B in the mixture, and 120 and 75 are constants.
To find the vapor pressure of pure component A, we need to consider the case where XB is equal to zero. This means that there is no component B present in the mixture. Substituting XB = 0 into the equation, we get:
PTotal = 120 - 75 * 0 PTotal = 120
Therefore, the vapor pressure of pure component A is 120 Torr.
To find the vapor pressure of pure component B, we need to consider the case where XB is equal to one. This means that the mixture is entirely composed of component B. Substituting XB = 1 into the equation, we get:
PTotal = 120 - 75 * 1 PTotal = 120 - 75 PTotal = 45
Therefore, the vapor pressure of pure component B is 45 Torr.
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