8)Bond order of O–O in the following molecule Na2O2 is 1.0 1.5 2.0 2.5
Question
8)Bond order of O–O in the following molecule Na2O2 is 1.0 1.5 2.0 2.5
Solution
The bond order of O–O in the molecule Na2O2 is 1.0.
Here's the step-by-step explanation:
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The molecule Na2O2 is sodium peroxide. In this molecule, each oxygen atom is linked to the other by a single bond.
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Bond order is defined as the number of chemical bonds between a pair of atoms. In sodium peroxide, there is only one bond between the two oxygen atoms.
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Therefore, the bond order of O–O in Na2O2 is 1.0.
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