Three capacitors are connected as shown. If C1 = 2 μF, C2 = 3 μF and C3 = 0.8 μF, then net work done by the battery in charging the capacitors will be100 μJ50 μJ25 μJ30 μJ

Two capacitors, each of capacitance 5 µF, are connected in series and then to a 100 V battery. The charge on each capacitor is:a) 250 µCb) 500 µCc) 1000 µCd) 2000 µC

Two capacitors (C1 = 8.00 µF and C2 = 13.0 µF) are now connected in series and to a 9.00-V battery.(a) Find the equivalent capacitance of the combination. µF(b) Find the potential difference across each capacitor.V1 = What is the relationship between the charges on each capacitor and the charge that would exist on an equivalent capacitor? VV2 = V(c) Find the charge on each capacitor.Q1 = µCQ2 = µC

Three identical capacitors are connected in series to give an equivalent total capacitance of 30 µF, what is the capacitance of each capacitor?*1 point90 µF10 µF60 µF20 µF

Suppose we consider the system of the three capacitors as a single "equivalent" capacitor. Given the charges of the three individual capacitors calculated in the previous part, find the total chargeQ_(tot )for this equivalent capacitor.\\nExpress your answer in terms of\\\\Delta VandC.\\nQ_(tot )=\\nRequest Answer

Two capacitors, one 12.0 𝜇𝐹 and the other of unknown capacitance C, are connected in parallel across a battery with an emf of 9.00 V. The total energy stored in the two capacitors is 0.0115 J. Determine the capacitance C.a.272 𝜇𝐹b.180 𝜇𝐹c.12 𝜇𝐹d.284𝜇𝐹