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A − (B ∪ C) = (A − B) − C.(3 marks)(b) Consider the sets S = {3, 5} and T = {2, 3, 7}. Indicate whether each of the followingstatements is true or false; no explanation is needed.(2 marks)(i) S ⊆ T(ii) ∅ ∈ P(S)(iii) ∅ ∈ T(iv) (3, 3, 3) ∈ S × T

Question

A − (B ∪ C) = (A − B) − C.(3 marks)(b) Consider the sets S = {3, 5} and T = {2, 3, 7}. Indicate whether each of the followingstatements is true or false; no explanation is needed.(2 marks)(i) S ⊆ T(ii) ∅ ∈ P(S)(iii) ∅ ∈ T(iv) (3, 3, 3) ∈ S × T

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Solution

(a) A − (B ∪ C) = (A − B) − C.

This statement is true. Here's how:

Step 1: B ∪ C means the union of sets B and C, which includes all elements that are in B, or in C, or in both.

Step 2: A - (B ∪ C) means the set of elements that are in A but not in the union of B and C.

Step 3: (A - B) means the set of elements that are in A but not in B.

Step 4: (A - B) - C means the set of elements that are in A, not in B, and also not in C.

So, A - (B ∪ C) is the same as (A - B) - C.

(b) Consider the sets S = {3, 5} and T = {2, 3, 7}.

(i) S ⊆ T

This statement is false. S is not a subset of T because 5 is in S but not in T.

(ii) ∅ ∈ P(S)

This statement is true. The power set P(S) includes all subsets of S, including the empty set ∅.

(iii) ∅ ∈ T

This statement is false. The empty set ∅ is not an element of T.

(iv) (3, 3, 3) ∈ S × T

This statement is false. The Cartesian product S × T includes all ordered pairs (s, t) where s is in S and t is in T. The triplet (3, 3, 3) is not included because it's not a pair and 3 is not in T twice.

This problem has been solved

Similar Questions

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