3.What will be the output of the program?public class CommandArgsTwo { public static void main(String [] argh) { int x; x = argh.length; for (int y = 1; y <= x; y++) { System.out.print(" " + argh[y]); } }}and the command-line invocation is> java CommandArgsTwo 1 2 3
Question
3.What will be the output of the program?public class CommandArgsTwo { public static void main(String [] argh) { int x; x = argh.length; for (int y = 1; y <= x; y++) { System.out.print(" " + argh[y]); } }}and the command-line invocation is> java CommandArgsTwo 1 2 3
Solution
The output of the program will be " 2 3".
Here's the step by step explanation:
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The program is a Java program that takes command line arguments.
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The command line invocation is "java CommandArgsTwo 1 2 3". This means that the program is being run with three arguments: 1, 2, and 3.
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In the program, the variable 'x' is assigned the length of the array 'argh', which is the array of command line arguments. In this case, 'x' will be 3 because there are three arguments.
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The program then enters a for loop that starts with 'y' equal to 1 and continues as long as 'y' is less than or equal to 'x'.
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Inside the loop, the program prints out the 'y'th element of the 'argh' array.
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Since 'y' starts at 1, the first element of the array (argh[0], which is '1') is skipped.
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The loop then continues with 'y' equal to 2, so it prints out the second element of the array (argh[1], which is '2').
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Finally, 'y' is incremented to 3, so it prints out the third element of the array (argh[2], which is '3').
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The loop then ends because 'y' is no longer less than or equal to 'x'.
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Therefore, the output of the program is " 2 3".
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