Find the Laplace transform of f(t) = 2𝑒7𝑡-2

The Laplace transform of a function f(t) = e^(at) is given by 1/(s-a) where s is a complex number frequency parameter.

For the function f(t) = 2e^(7t) - 2, we can break it down into two separate functions for the purpose of the Laplace transform: f1(t) = 2e^(7t) and f2(t) = -2.

The Laplace transform of f1(t) = 2e^(7t) is 2/(s-7) using the formula mentioned above.

The Laplace transform of a constant c is c/s. So, the Laplace transform of f2(t) = -2 is -2/s.

Therefore, the Laplace transform of f(t) = 2e^(7t) - 2 is 2/(s-7) - 2/s.