If C(3, 8) is the third vertex of triangle ABC then what is the altitudefrom C to AB?Answer any four questions. Each carries 3 scores5) The vertices of a triangle are on a circle.∠A = 60◦, BC = 10cma) Draw the diameter BP and join P C.What are the angles of triangleBP Cb) What is the radius of the circle?6) In the figure P A and P B are the tangents from P to the circle.∠AP B = 40◦a) What is the measure of ∠AOB?b) Find ∠ACB and ∠ADB?7) a) Draw co-ordinate axes and mark the points A(4, 0), B(0, 4), C(−4, 0)and D(0, −4).b) Suggest a suitable name to ABCD.c) Find the area of ABCD.

5. To find the altitude from C to AB, we need to determine the height of the triangle.

a) Since C(3, 8) is the third vertex of triangle ABC, we can draw a line segment from C perpendicular to AB. Let's call the point where the altitude intersects AB as D.

b) To find the angles of triangle BPC, we can use the fact that the sum of angles in a triangle is 180 degrees. Since BP is a diameter of the circle, angle BPC is a right angle (90 degrees). Therefore, angle BCP is also 90 degrees.

6. In the given figure, let's consider triangle AOB.

a) Since ∠APB is 40 degrees and AP and BP are tangents to the circle, we know that ∠APB is equal to ∠AOB. Therefore, ∠AOB is also 40 degrees.

b) To find ∠ACB and ∠ADB, we need more information about the positions of points C and D.

a) To draw the coordinate axes, we can draw two perpendicular lines intersecting at the origin (0, 0). Let's label the horizontal axis as x-axis and the vertical axis as y-axis.

b) A suitable name for the quadrilateral ABCD could be a square, since the given points A, B, C, and D form a square shape.

c) To find the area of ABCD, we can use the formula for the area of a square, which is side length squared. The side length of ABCD can be found by calculating the distance between any two adjacent points. In this case, the distance between A(4, 0) and B(0, 4) is 4 units. Therefore, the area of ABCD is 4^2 = 16 square units.