Value of m if 3y = 3x + 5 is ⊥ to mx + 2y 8 = 0 isA.-3B.2C.3D.-2

To find the value of m if the equation 3y = 3x + 5 is perpendicular to mx + 2y + 8 = 0, we need to compare the slopes of the two equations.

First, let's rewrite the second equation in slope-intercept form (y = mx + b): mx + 2y + 8 = 0 2y = -mx - 8 y = (-1/2)m - 4

Comparing this equation to the first equation, we can see that the slope of the first equation is 3, while the slope of the second equation is -1/2.

For two lines to be perpendicular, the product of their slopes must be -1. Therefore, we can set up the following equation:

3 * (-1/2) = -1

Simplifying this equation, we get:

-3/2 = -1

Since this equation is not true, we can conclude that the value of m does not exist for the given conditions. Therefore, none of the options A, B, C, or D is the correct answer.