Solve the quadratic by factoring.3, x, squared, plus, 16, x, plus, 1, equals, 9, x, minus, 33x 2 +16x+1=9x−3
Question
Solve the quadratic by factoring.3, x, squared, plus, 16, x, plus, 1, equals, 9, x, minus, 33x 2 +16x+1=9x−3
Solution
The equation you've provided seems to have a typo. It's not clear where the "minus 33x" fits in. However, if the equation is 3x^2 + 16x + 1 = 9x - 3, here's how you would solve it:
Step 1: Rearrange the equation to set it equal to zero.
3x^2 + 16x - 9x + 1 + 3 = 0
This simplifies to:
3x^2 + 7x + 4 = 0
Step 2: Factor the quadratic equation.
This equation can be factored into:
(3x + 4)(x + 1) = 0
Step 3: Set each factor equal to zero and solve for x.
3x + 4 = 0 --> 3x = -4 --> x = -4/3
x + 1 = 0 --> x = -1
So, the solutions to the equation are x = -4/3 and x = -1.
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