Find the probability. Write your answer as a fraction.A box of chocolates contains seven milk chocolates and six dark chocolates. Four of the milk chocolates and five of the dark chocolates have peanuts inside. You randomly select and eat a chocolate. It is a dark chocolate or has peanuts inside.Answer

To solve this problem, we need to find the total number of chocolates, the number of dark chocolates, and the number of chocolates with peanuts.

1. Total number of chocolates = 7 milk chocolates + 6 dark chocolates = 13 chocolates

2. Number of dark chocolates = 6

3. Number of chocolates with peanuts = 4 milk chocolates with peanuts + 5 dark chocolates with peanuts = 9 chocolates

We are looking for the probability that the chocolate selected is either a dark chocolate or a chocolate with peanuts. This can be calculated using the formula for the probability of the union of two events: P(A or B) = P(A) + P(B) - P(A and B).

4. Probability of selecting a dark chocolate (P(D)) = Number of dark chocolates / Total number of chocolates = 6/13

5. Probability of selecting a chocolate with peanuts (P(P)) = Number of chocolates with peanuts / Total number of chocolates = 9/13

6. Probability of selecting a dark chocolate with peanuts (P(D and P)) = Number of dark chocolates with peanuts / Total number of chocolates = 5/13

Now we can substitute these values into the formula:

P(D or P) = P(D) + P(P) - P(D and P) = 6/13 + 9/13 - 5/13 = 10/13

So, the probability that the chocolate selected is either a dark chocolate or has peanuts inside is 10/13.