This problem can be solved using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Step 1: Identify the sides of the right triangle. In this case, the ladder is the hypotenuse, the house is one side, and the ground is the other side.

Step 2: Use the Pythagorean theorem to find the original distance from the base of the ladder to the house. The ladder is 25 feet long and reaches 15 feet up the house, so we can set up the equation 25^2 = 15^2 + b^2, where b is the base of the triangle. Solving for b gives us b = sqrt(25^2 - 15^2) = 20 feet.

Step 3: Now, Camden pulls the ladder 3 feet farther from the house, so the new base of the triangle is 20 + 3 = 23 feet.

Step 4: Use the Pythagorean theorem again to find the new height that the ladder reaches up the house. We know the ladder is still 25 feet long and the base is now 23 feet, so we can set up the equation 25^2 = h^2 + 23^2, where h is the new height. Solving for h gives us h = sqrt(25^2 - 23^2) = 10 feet.

So, after Camden pulls the ladder 3 feet farther from the house, it will reach approximately 10 feet up the side of the house.

Question

This problem can be solved using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Step 1: Identify the sides of the right triangle. In this case, the ladder is the hypotenuse, the house is one side, and the ground is the other side.

Step 2: Use the Pythagorean theorem to find the original distance from the base of the ladder to the house. The ladder is 25 feet long and reaches 15 feet up the house, so we can set up the equation 25^2 = 15^2 + b^2, where b is the base of the triangle. Solving for b gives us b = sqrt(25^2 - 15^2) = 20 feet.

Step 3: Now, Camden pulls the ladder 3 feet farther from the house, so the new base of the triangle is 20 + 3 = 23 feet.

Step 4: Use the Pythagorean theorem again to find the new height that the ladder reaches up the house. We know the ladder is still 25 feet long and the base is now 23 feet, so we can set up the equation 25^2 = h^2 + 23^2, where h is the new height. Solving for h gives us h = sqrt(25^2 - 23^2) = 10 feet.

So, after Camden pulls the ladder 3 feet farther from the house, it will reach approximately 10 feet up the side of the house.

Knowee AI · Accepted Answer

This problem can be solved using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Step 1: Identify the sides of the right triangle. In this case, the ladder is the hypotenuse, the house is one side, and the ground is the other side.

Step 2: Use the Pythagorean theorem to find the original distance from the base of the ladder to the house. The ladder is 25 feet long and reaches 15 feet up the house, so we can set up the equation 25^2 = 15^2 + b^2, where b is the base of the triangle. Solving for b gives us b = sqrt(25^2 - 15^2) = 20 feet.

Step 3: Now, Camden pulls the ladder 3 feet farther from the house, so the new base of the triangle is 20 + 3 = 23 feet.

Step 4: Use the Pythagorean theorem again to find the new height that the ladder reaches up the house. We know the ladder is still 25 feet long and the base is now 23 feet, so we can set up the equation 25^2 = h^2 + 23^2, where h is the new height. Solving for h gives us h = sqrt(25^2 - 23^2) = 10 feet.

So, after Camden pulls the ladder 3 feet farther from the house, it will reach approximately 10 feet up the side of the house.

A 25 foot ladder is set against the side of a house so that it reaches up 15 feet. If Camden grabs the ladder at its base and pulls it 3 feet farther from the house, how far up the side of the house will the ladder reach now? (The answer is not 12 ft.) Round to the nearest tenth of a foot.

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