In an AP, 7 times 7th term is equal to 8 times 8th term. Then its 15th termis ....
Question
In an AP, 7 times 7th term is equal to 8 times 8th term. Then its 15th termis ....
Solution
Sure, let's solve this step by step.
Given that in an Arithmetic Progression (AP), 7 times the 7th term is equal to 8 times the 8th term. This can be written as:
7 * (a + 6d) = 8 * (a + 7d)
where 'a' is the first term and 'd' is the common difference.
Solving this equation, we get:
7a + 42d = 8a + 56d
This simplifies to:
a = 14d
Now, we need to find the 15th term of the AP. The nth term of an AP is given by:
Tn = a + (n - 1) * d
Substituting n = 15, a = 14d in the above equation, we get:
T15 = 14d + (15 - 1) * d
This simplifies to:
T15 = 14d + 14d = 28d
So, the 15th term of the AP is 28 times the common difference. Without knowing the common difference, we cannot find the exact value of the 15th term.
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