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How many 3-digit odd numbers exist, with no repetition? Ex: 871 counts, but 777 does not.

Question

How many 3-digit odd numbers exist, with no repetition? Ex: 871 counts, but 777 does not.

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Solution

Sure, let's break it down:

  1. A 3-digit number has three places: hundreds, tens, and units.

  2. Since the number is odd, the unit place can be filled by any of the 5 odd numbers from 0 to 9, which are 1, 3, 5, 7, and 9.

  3. The hundreds place can be filled by any of the remaining 9 digits (0 can't be used because it's a 3-digit number).

  4. Finally, the tens place can be filled by any of the remaining 8 digits.

So, the total number of 3-digit odd numbers with no repetition is 5 (choices for the units place) * 9 (choices for the hundreds place) * 8 (choices for the tens place) = 360.

This problem has been solved

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