What will be the output of the following program?#include <iostream>using namespace std;int main() { int i = 3; int l = i / -2; int k = i % -2; cout << l << " " << k; return 0; }Select one:-1.5 -1-1.5 -1.97-1 1-1 -1
Question
What will be the output of the following program?#include <iostream>using namespace std;int main() { int i = 3; int l = i / -2; int k = i % -2; cout << l << " " << k; return 0; }Select one:-1.5 -1-1.5 -1.97-1 1-1 -1
Solution
The output of the program will be "-1 1".
Here's the step by step explanation:
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The program starts with the inclusion of the iostream library which allows the program to perform input and output operations.
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The namespace std is declared to avoid the need of using std:: before every standard library object.
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The main function is declared. This is the function that is executed when the program runs.
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Inside the main function, an integer variable 'i' is declared and initialized with the value 3.
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Then, another integer variable 'l' is declared and it is assigned the value of 'i' divided by -2. Since 'i' is 3, the division operation results in -1.5. But since 'l' is an integer, it can only hold integer values and the decimal part is truncated. So, 'l' becomes -1.
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Next, an integer variable 'k' is declared and it is assigned the value of 'i' modulo -2. The modulo operation gives the remainder of the division of 'i' by -2. Since 3 divided by -2 gives a remainder of 1, 'k' becomes 1.
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The cout statement is used to print the values of 'l' and 'k' separated by a space. So, it prints "-1 1".
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The return 0 statement signifies that the program has executed successfully without any errors.
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