Potassium dichromate acts as a strong oxidizing agent in acidic solution. During this process, the oxidation state changes from
Question
Potassium dichromate acts as a strong oxidizing agent in acidic solution. During this process, the oxidation state changes from
Solution
In an acidic solution, potassium dichromate (K2Cr2O7) acts as a strong oxidizing agent. During this process, the oxidation state of chromium changes from +6 to +3.
Here's the step-by-step process:
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The chemical formula for potassium dichromate is K2Cr2O7. In this compound, the oxidation state of chromium (Cr) is +6.
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When potassium dichromate is used as an oxidizing agent in an acidic solution, it gets reduced to Cr3+.
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The reduction half-reaction is: Cr2O7^2- + 14H+ + 6e- → 2Cr3+ + 7H2O. This shows that each chromium atom is reduced from an oxidation state of +6 to +3.
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Therefore, during this process, the oxidation state of chromium changes from +6 to +3.
Similar Questions
The oxidation state of chromium in the final product formed by the reaction between KI and acidified potassium dichromate solution is+4+6+2+3
Acidified potassium dichromate is treated with hydrogen sulphide. In the reaction, the oxidation number of chromiumIncreases from +3 to +6Decreases from +6 to +3Remains unchangedDecreases from +6 to +2
oxidation state of potassium
Oxidation state of chromium in K3CrO8 is
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