The ages of two persons differ by 20 years. If 5 years ago, the elder one be 5 times as old as the younger one, their present ages (in years) are respectively?Options50, 3025, 530, 1029, 9
Question
The ages of two persons differ by 20 years. If 5 years ago, the elder one be 5 times as old as the younger one, their present ages (in years) are respectively?Options50, 3025, 530, 1029, 9
Solution
Let's denote the present age of the elder person as E and the present age of the younger person as Y.
From the problem, we know that:
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E = Y + 20 (since their ages differ by 20 years)
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E - 5 = 5 * (Y - 5) (since 5 years ago, the elder one was 5 times as old as the younger one)
We can substitute E from the first equation into the second equation to solve for Y:
(Y + 20) - 5 = 5 * (Y - 5)
Solving this equation gives Y = 10.
Substituting Y = 10 into the first equation gives E = 10 + 20 = 30.
So, the present ages of the elder and younger person are 30 and 10 years, respectively.
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