What is the molarity of a solution prepared by dissolving 317 g of CaCl2 (calcium chloride) into enough water to make 2.50 L of solution? (MW CaCl2 = 110.98 g/mol) _______ M Your answer should be rounded to three significant figures. Do not include units in your answer.
Question
What is the molarity of a solution prepared by dissolving 317 g of CaCl2 (calcium chloride) into enough water to make 2.50 L of solution?
(MW CaCl2 = 110.98 g/mol)
_______ M
Your answer should be rounded to three significant figures. Do not include units in your answer.
Solution
To calculate the molarity of the solution, we need to follow these steps:
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Convert the mass of CaCl2 into moles. We do this by dividing the mass by the molar mass.
Moles of CaCl2 = 317 g / 110.98 g/mol = 2.857 moles (rounded to three decimal places)
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Next, we calculate the molarity by dividing the number of moles of solute by the volume of the solution in liters.
Molarity = Moles of solute / Volume of solution in liters Molarity = 2.857 moles / 2.50 L = 1.143 M (rounded to three decimal places)
So, the molarity of the solution is 1.143 M.
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