P, Q, R are three cups having capacities of 120, 180 and 200 cc respectively which are completely filled with tea of three different varieties. They are all mixed in a separate vessel of capacity more than that of P, Q, R taken together, and then the mixture is poured successively into P, Q, R Then how much (in cc) of Pand Q’s tea will be there in R?
Question
P, Q, R are three cups having capacities of 120, 180 and 200 cc respectively which are completely filled with tea of three different varieties. They are all mixed in a separate vessel of capacity more than that of P, Q, R taken together, and then the mixture is poured successively into P, Q, R Then how much (in cc) of Pand Q’s tea will be there in R?
Solution
The total capacity of cups P, Q, and R is 120 cc + 180 cc + 200 cc = 500 cc.
When all the tea from cups P, Q, and R is mixed together in a separate vessel, the tea from each cup is evenly distributed throughout the mixture.
Therefore, the amount of tea from each cup in the mixture is 500 cc / 3 = 166.67 cc.
When the mixture is poured back into cups P, Q, and R, each cup will contain the same proportion of tea from each original cup.
Therefore, the amount of tea from cups P and Q in cup R is 166.67 cc * 2/3 = 111.11 cc.
So, there will be approximately 111 cc of tea from cups P and Q in cup R.
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