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Block A𝐴 in (Figure 1) has mass 1.00 kgkg, and block B𝐵 has mass 3.00 kgkg. The blocks are forced together, compressing a spring S𝑆 between them; then the system is released from rest on a level, frictionless surface. The spring, which has negligible mass, is not fastened to either block and drops to the surface after it has expanded. Block B𝐵 acquires a speed of 1.30 m/sm/s.Figure1 of 1Part AWhat is the final speed of block A𝐴?Express your answer in meters per second.Activate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typev𝑣 =nothingm/sm/sSubmitRequest AnswerPart BHow much potential energy was stored in the compressed spring?Express your answer in joules.Activate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeU𝑈 =

Question

Block A𝐴 in (Figure 1) has mass 1.00 kgkg, and block B𝐵 has mass 3.00 kgkg. The blocks are forced together, compressing a spring S𝑆 between them; then the system is released from rest on a level, frictionless surface. The spring, which has negligible mass, is not fastened to either block and drops to the surface after it has expanded. Block B𝐵 acquires a speed of 1.30 m/sm/s.Figure1 of 1Part AWhat is the final speed of block A𝐴?Express your answer in meters per second.Activate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typev𝑣 =nothingm/sm/sSubmitRequest AnswerPart BHow much potential energy was stored in the compressed spring?Express your answer in joules.Activate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeU𝑈 =

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Solution

Part A

To find the final speed of block A, we can use the principle of conservation of momentum. The total momentum before the spring is released is zero (since both blocks are at rest), so the total momentum after the spring is released must also be zero.

Let's denote the final speed of block A as vA and the final speed of block B as vB. The mass of block A is mA = 1.00 kg and the mass of block B is mB = 3.00 kg.

According to the conservation of momentum:

mA * vA + mB * vB = 0

We know that vB = 1.30 m/s, so we can substitute this into the equation:

vA = - (mB * vB) / mA vA = - (3.00 kg * 1.30 m/s) / 1.00 kg vA = - 3.90 m/s

The negative sign indicates that block A is moving in the opposite direction to block B. Therefore, the final speed of block A is 3.90 m/s.

Part B

The potential energy stored in the spring can be found using the principle of conservation of energy. The total kinetic energy of the blocks after the spring is released is equal to the potential energy stored in the spring before it was released.

The kinetic energy KE of an object is given by the formula KE = 0.5 * m * v^2, where m is the mass of the object and v is its speed.

The total kinetic energy of the blocks is therefore:

KE = 0.5 * mA * vA^2 + 0.5 * mB * vB^2 KE = 0.5 * 1.00 kg * (3.90 m/s)^2 + 0.5 * 3.00 kg * (1.30 m/s)^2 KE = 7.605 J

Therefore, the potential energy stored in the spring was 7.605 J.

This problem has been solved

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