A long wire carries a current of 2 A. Find the magnitude of the magnetic field 2 m away from the wire.*1 point2.0 x 10^-3 T2.0 x 10^-4 T2.0 x 10^-6 T2.0 x 10^-7 T
Question
A long wire carries a current of 2 A. Find the magnitude of the magnetic field 2 m away from the wire.*1 point2.0 x 10^-3 T2.0 x 10^-4 T2.0 x 10^-6 T2.0 x 10^-7 T
Solution
The magnetic field around a long straight wire can be calculated using Ampere's Law, which states that the magnetic field (B) at a distance (r) from a long straight wire carrying a current (I) is given by the formula:
B = μ0 * I / (2πr)
where μ0 is the permeability of free space, a constant equal to 4π x 10^-7 T m/A.
Substituting the given values into the formula:
B = (4π x 10^-7 T m/A * 2 A) / (2π * 2 m)
Simplifying the equation gives:
B = 2.0 x 10^-7 T
So, the magnitude of the magnetic field 2 m away from the wire is 2.0 x 10^-7 T.
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