To find g(x), which is the translation of f(x) = -9(x-4)^2 - 8 two units down, you simply subtract 2 from the constant term in the function f(x).

The function f(x) is in the form of a quadratic function, f(x) = a(x-h)^2 + k, where (h, k) is the vertex of the parabola. In this case, a = -9, h = 4, and k = -8.

When you translate a function down by 2 units, you subtract 2 from the k value. So, the new k value is -8 - 2 = -10.

Therefore, the function g(x) is g(x) = -9(x-4)^2 - 10.

Question

To find g(x), which is the translation of f(x) = -9(x-4)^2 - 8 two units down, you simply subtract 2 from the constant term in the function f(x).

The function f(x) is in the form of a quadratic function, f(x) = a(x-h)^2 + k, where (h, k) is the vertex of the parabola. In this case, a = -9, h = 4, and k = -8.

When you translate a function down by 2 units, you subtract 2 from the k value. So, the new k value is -8 - 2 = -10.

Therefore, the function g(x) is g(x) = -9(x-4)^2 - 10.

Knowee AI · Accepted Answer

To find g(x), which is the translation of f(x) = -9(x-4)^2 - 8 two units down, you simply subtract 2 from the constant term in the function f(x).

The function f(x) is in the form of a quadratic function, f(x) = a(x-h)^2 + k, where (h, k) is the vertex of the parabola. In this case, a = -9, h = 4, and k = -8.

When you translate a function down by 2 units, you subtract 2 from the k value. So, the new k value is -8 - 2 = -10.

Therefore, the function g(x) is g(x) = -9(x-4)^2 - 10.

Find g(x), where g(x) is the translation 2 units down of f(x)=–9(x–4)2–8.

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