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In a full wave rectifier employing two diodes, if a capacitor filter is connected across the load then*2 pointsRipple factor is increased and PIV rating of each is reducedEfficiency is increased and ripple factor is also increased.Ripple factor is reduced and PIV of each diode remains same.Amplitude of the output signal is increased and efficiency is also increased.

Question

In a full wave rectifier employing two diodes, if a capacitor filter is connected across the load then*2 pointsRipple factor is increased and PIV rating of each is reducedEfficiency is increased and ripple factor is also increased.Ripple factor is reduced and PIV of each diode remains same.Amplitude of the output signal is increased and efficiency is also increased.

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Solution

The correct answer is: Ripple factor is reduced and PIV of each diode remains same.

Here's why:

  1. A full wave rectifier with a capacitor filter is designed to reduce the ripple factor, which is a measure of the fluctuation in the output voltage. The capacitor filter smooths the output, reducing the ripple.

  2. The Peak Inverse Voltage (PIV) rating of each diode is a measure of the maximum voltage a diode can withstand in the reverse bias condition. This is determined by the characteristics of the diode itself and the circuit design, not by the presence of a capacitor filter. Therefore, the PIV of each diode remains the same.

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