In this challenge, you must read integers from stdin and then print them to stdout. Each integer must be printed on a new line. To make the problem a little easier, a portion of the code is provided for you in the editor below.
Question
In this challenge, you must read integers from stdin and then print them to stdout. Each integer must be printed on a new line. To make the problem a little easier, a portion of the code is provided for you in the editor below.
Solution
Here is a step-by-step guide to solve this problem:
-
First, you need to read the number of integers you are going to input. You can do this using the
input()function which reads a line from input, converts it to a string and returns that. If you want to read an integer, you can useint(input()). -
Then, you need to read each integer. You can do this in a loop. The number of iterations of the loop will be the number of integers you read in the first step. In each iteration, you read an integer using
int(input())and store it in a variable. -
After reading each integer, you need to print it. You can do this using the
print()function. You pass the integer you just read to this function and it will print it. -
Repeat steps 2 and 3 for the number of integers you read in the first step.
Here is a Python code snippet that does this:
n = int(input())
for _ in range(n):
number = int(input())
print(number)
In this code, _ is a variable that we don't care about. It's a convention in Python to use _ for throwaway variables. It's not used anywhere in the loop. The important part is range(n), which generates a sequence of numbers from 0 to n-1, and the loop iterates over this sequence. In each iteration, it reads an integer and prints it.
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