A nugget of gold with a mass of 521 g is added to 50.0 mL of water. The water level rises to a volume of 77.0 mL. What is the density of the gold?Group of answer choices1.00 g/mL6.77 g/mL19.3 g/mL10.4 g/mL0.0518 g/mL
Question
A nugget of gold with a mass of 521 g is added to 50.0 mL of water. The water level rises to a volume of 77.0 mL. What is the density of the gold?Group of answer choices1.00 g/mL6.77 g/mL19.3 g/mL10.4 g/mL0.0518 g/mL
Solution
To find the density of the gold, we need to use the formula for density, which is mass divided by volume.
Step 1: Find the volume of the gold. The volume of the gold can be found by subtracting the initial volume of the water from the final volume of the water after the gold is added.
So, Volume of gold = Final volume - Initial volume = 77.0 mL - 50.0 mL = 27.0 mL
Step 2: Convert the mass of the gold to the same units as the volume. The mass of the gold is given in grams (g), which is already in the correct units, so no conversion is necessary.
Step 3: Calculate the density of the gold. Density = Mass / Volume = 521 g / 27.0 mL = 19.3 g/mL
So, the density of the gold is 19.3 g/mL.
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