The prices of two articles are in the ratio 3: 2. If the price of the first article be increased by 10% and that of the second by Rs. 4, the original ratio remains the same. The original price of the second article is
Question
The prices of two articles are in the ratio 3: 2. If the price of the first article be increased by 10% and that of the second by Rs. 4, the original ratio remains the same. The original price of the second article is
Solution
Let's denote the original prices of the first and second articles as 3x and 2x respectively.
According to the problem, after the price of the first article is increased by 10% and the price of the second article is increased by Rs. 4, the ratio remains the same. This can be written as:
(3x * 1.10) / (2x + 4) = 3/2
Solving this equation will give us the value of x, which we can then use to find the original price of the second article (2x).
First, let's simplify the equation:
3.3x / (2x + 4) = 3/2
Cross-multiplying gives us:
6.6x = 3 * (2x + 4)
Solving for x gives us:
6.6x = 6x + 12
Subtract 6x from both sides:
0.6x = 12
Finally, divide both sides by 0.6 to solve for x:
x = 12 / 0.6 = 20
So, the original price of the second article is 2x = 2 * 20 = Rs. 40.
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