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A power-generating windmill is being designed and will consist of a tower with three large blades that rotate on a central hub at the top of the tower. The height of the tower from the ground to the center of the hub where the 3 blades meet is 262⁢ feet, and the length of the blades from the center of the hub to the tip of each blade is 148 feet. The tower is in the shape of a right circular cylinder that has a diameter of 40 feet, as shown in the figure.QuestionThe windmill’s tower extends from the ground to the center of the hub. Which of the following is closest to the volume of the windmill’s tower?

Question

A power-generating windmill is being designed and will consist of a tower with three large blades that rotate on a central hub at the top of the tower. The height of the tower from the ground to the center of the hub where the 3 blades meet is 262⁢ feet, and the length of the blades from the center of the hub to the tip of each blade is 148 feet. The tower is in the shape of a right circular cylinder that has a diameter of 40 feet, as shown in the figure.QuestionThe windmill’s tower extends from the ground to the center of the hub. Which of the following is closest to the volume of the windmill’s tower?

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Solution

To find the volume of the windmill's tower, we need to use the formula for the volume of a right circular cylinder, which is given by:

V=πr2h V = \pi r^2 h

where:

  • V V is the volume,
  • r r is the radius of the base of the cylinder,
  • h h is the height of the cylinder.

From the problem, we know:

  • The height h h of the tower is 262 feet.
  • The diameter of the base of the tower is 40 feet, so the radius r r is half of the diameter, which is 402=20 \frac{40}{2} = 20 feet.

Now, we can plug these values into the formula:

V=π(20)2(262) V = \pi (20)^2 (262)

First, calculate the radius squared:

202=400 20^2 = 400

Next, multiply by the height:

400×262=104800 400 \times 262 = 104800

Finally, multiply by π \pi :

V=104800π V = 104800 \pi

Using the approximation π3.14159 \pi \approx 3.14159 :

V104800×3.14159 V \approx 104800 \times 3.14159 V329,867.432 V \approx 329,867.432

Therefore, the volume of the windmill’s tower is closest to 329,867 cubic feet.

This problem has been solved

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