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According to the records of a soft drink company, the bottles for their one-liter-sized products contain an average (mean) of 1.02 liters of beverage, with a standard deviation of 0.13 liters. As part of routine quality assurance, a sample of 60 bottles has been taken. The sample mean amount of beverage in these 60 bottles was 0.982 liters.Assuming the company's records are correct, find the probability of observing a sample mean of 0.982 liters or less in a sample of 60 bottles.Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.

Question

According to the records of a soft drink company, the bottles for their one-liter-sized products contain an average (mean) of 1.02 liters of beverage, with a standard deviation of 0.13 liters. As part of routine quality assurance, a sample of 60 bottles has been taken. The sample mean amount of beverage in these 60 bottles was 0.982 liters.Assuming the company's records are correct, find the probability of observing a sample mean of 0.982 liters or less in a sample of 60 bottles.Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.

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Solution

To solve this problem, we will use the concept of Z-score in statistics. The Z-score is a measure of how many standard deviations an element is from the mean.

Step 1: Identify the given values. The population mean (μ) = 1.02 liters The population standard deviation (σ) = 0.13 liters The sample size (n) = 60 bottles The sample mean (x̄) = 0.982 liters

Step 2: Calculate the standard error of the mean (σx̄). The standard error of the mean is the standard deviation of the sampling distribution of the mean. It is calculated as the standard deviation divided by the square root of the sample size. σx̄ = σ/√n = 0.13/√60 = 0.0168 (rounded to four decimal places)

Step 3: Calculate the Z-score. The Z-score is calculated as the difference between the sample mean and the population mean, divided by the standard error of the mean. Z = (x̄ - μ)/σx̄ = (0.982 - 1.02)/0.0168 = -2.262 (rounded to three decimal places)

Step 4: Find the probability. The Z-score of -2.262 corresponds to a left-tail probability. We can look up this Z-score in a standard normal distribution table or use a calculator with a normal distribution function to find the probability. The probability that corresponds to a Z-score of -2.262 is approximately 0.012 (rounded to three decimal places).

So, the probability of observing a sample mean of 0.982 liters or less in a sample of 60 bottles is approximately 0.012 or 1.2%.

This problem has been solved

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