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A right circular cone is cut (parallel to its base) into five slices, all of the same height. What is the ratio of the volume of the middle slice to that of the biggest slice?

Question

A right circular cone is cut (parallel to its base) into five slices, all of the same height. What is the ratio of the volume of the middle slice to that of the biggest slice?

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Solution

To solve this problem, we need to understand that the volume of a cone is proportional to the square of its radius. This is because the formula for the volume of a cone is (1/3)πr²h, where r is the radius and h is the height.

Since the cone is cut into five slices of equal height, the radius of each slice will be 1/5, 2/5, 3/5, 4/5, and 5/5 (or 1) of the original radius.

The ratio of the volume of the middle slice (with radius 3/5) to the biggest slice (with radius 1) will be:

[(1/3)π(3/5)²h] / [(1/3)π(1)²h] = (9/25) / (1) = 9/25

So, the ratio of the volume of the middle slice to that of the biggest slice is 9:25.

This problem has been solved

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