Train A covers 200 km in 30 minutes less time than train B. Train B travels 20km/h slower than train A.An equation which could be used to solve for b, the speed of train B, is: Responses
Question
Train A covers 200 km in 30 minutes less time than train B. Train B travels 20km/h slower than train A.An equation which could be used to solve for b, the speed of train B, is: Responses
Solution
The first step is to understand the problem. We know that speed is equal to distance divided by time. We also know that Train A travels 200 km in 30 minutes less time than Train B.
Let's denote:
- the speed of Train A as a (km/h)
- the speed of Train B as b (km/h)
- the time Train A takes as t1 (hours)
- the time Train B takes as t2 (hours)
From the problem, we know that:
- a = b + 20 (since Train A travels 20km/h faster than Train B)
- t1 = t2 - 0.5 (since Train A takes 30 minutes, or 0.5 hours, less than Train B)
We can express the time each train takes to cover the 200 km in terms of their speeds:
- t1 = 200/a
- t2 = 200/b
Substituting the expressions for t1 and t2 from the speed equations into the time equations gives us:
- 200/a = 200/b - 0.5
- 200/b = 200/a + 0.5
We can rearrange the first equation to solve for b: 200/b = 200/a + 0.5 b = 200 / (200/a + 0.5)
Substituting a = b + 20 into this equation gives us the final equation to solve for b: b = 200 / (200/(b + 20) + 0.5)
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