The roots of the quadratic equation x^2 - 5x + 6 = 0 can be found using the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

Here, a = 1, b = -5, and c = 6.

First, calculate the value under the square root, b^2 - 4ac = (-5)^2 - 4*1*6 = 25 - 24 = 1.

Then, calculate the two possible values for x:

x1 = [-(-5) + sqrt(1)] / (2*1) = (5 + 1) / 2 = 3
x2 = [-(-5) - sqrt(1)] / (2*1) = (5 - 1) / 2 = 2

So, the roots of the equation are x = 2 and x = 3. Therefore, the correct answer is d. x = 2, x = 3.

Question

The roots of the quadratic equation x^2 - 5x + 6 = 0 can be found using the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

Here, a = 1, b = -5, and c = 6.

First, calculate the value under the square root, b^2 - 4ac = (-5)^2 - 4*1*6 = 25 - 24 = 1.

Then, calculate the two possible values for x:

x1 = [-(-5) + sqrt(1)] / (2*1) = (5 + 1) / 2 = 3
x2 = [-(-5) - sqrt(1)] / (2*1) = (5 - 1) / 2 = 2

So, the roots of the equation are x = 2 and x = 3. Therefore, the correct answer is d. x = 2, x = 3.

Knowee AI · Accepted Answer

The roots of the quadratic equation x^2 - 5x + 6 = 0 can be found using the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

Here, a = 1, b = -5, and c = 6.

First, calculate the value under the square root, b^2 - 4ac = (-5)^2 - 4*1*6 = 25 - 24 = 1.

Then, calculate the two possible values for x:

x1 = [-(-5) + sqrt(1)] / (2*1) = (5 + 1) / 2 = 3
x2 = [-(-5) - sqrt(1)] / (2*1) = (5 - 1) / 2 = 2

So, the roots of the equation are x = 2 and x = 3. Therefore, the correct answer is d. x = 2, x = 3.

What are the roots of the quadratic equation x^2 - 5x + 6 = 0 ?a.x = -2, x = -3b.x = -2, x = 3c.x = 2, x = -3d.x = 2, x = 3